[Python] A simple way to sort a dictionary

	>>> import operator
	>>> x #x is a dictionary
	{'cde': 456, 'abc': 789, 'efg': 123}
	# only return keys
	>>> sorted(x)
	['abc', 'cde', 'efg']
	# sort by key, "reverse=True" means from large to small
	>>> sorted(x.items(), key=operator.itemgetter(0), reverse=True)
	[('efg', 123), ('cde', 456), ('abc', 789)]
	# sort by value, just change the parameter in the itemgetter()
	>>> sorted(x.items(), key=operator.itemgetter(1), reverse=True)
	[('abc', 789), ('cde', 456), ('efg', 123)]

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